Find the exponential function that contains the points 2 10 and 3 5

An exponential function is in the general form

#y=a(b)^x#

We know the points #(-1,8)# and #(1,2)#, so the following are true:

#8=a(b^-1)=a/b#

#2=a(b^1)=ab#

Multiply both sides of the first equation by #b# to find that

#8b=a#

Plug this into the second equation and solve for #b#:

#2=(8b)b#

#2=8b^2#

#b^2=1/4#

#b=+-1/2#

Two equations seem to be possible here. Plug both values of #b# into the either equation to find #a#. I'll use the second equation for simpler algebra.

If#b=1/2#:

#2=a(1/2)#

#a=4#

Giving us the equation: #color(green)(y=4(1/2)^x#

If#b=-1/2#:

#2=a(-1/2)#

#a=-4#

Giving us the equation: #y=-4(-1/2)^x#

However! In an exponential function, #b>0#, otherwise many issues arise when trying to graph the function.

The only valid function is

#color(green)(y=4(1/2)^x#

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How do you find an exponential function given two points?

If you have two points, (x1, y1) and (x2, y2), you can define the exponential function that passes through these points by substituting them in the equation y = abx and solving for a and b. In general, you have to solve this pair of equations: y1 = abx1 and y2 = abx2, .

How do you find a and b in an exponential function?

Using a, substitute the second point into the equation f(x)=abx f ( x ) = a b x and solve for b. If neither of the data points have the form (0,a) , substitute both points into two equations with the form f(x)=abx f ( x ) = a b x . Solve the resulting system of two equations to find a and b.

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